4x^2-50x-8=0

Solution for 4x^2-50x-8=0 equation:

4x^2-50x-8=0

a = 4; b = -50; c = -8;
Δ = b2-4ac
Δ = -502-4·4·(-8)
Δ = 2628
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2628}=\sqrt{36*73}=\sqrt{36}*\sqrt{73}=6\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-6\sqrt{73}}{2*4}=\frac{50-6\sqrt{73}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+6\sqrt{73}}{2*4}=\frac{50+6\sqrt{73}}{8}
$